Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 7 - Section 7.1 - Ratio - Exercises: 31

Answer

$\frac{3}{8}$ lb/gal

Work Step by Step

$\frac{2\frac{1}{4}lb}{6gal}=\frac{\frac{9}{4}lb}{6gal}=\frac{9}{4}\times\frac{1}{6}lb/gal=\frac{/\!\!3\times3}{4}\times\frac{1}{/\!\!3\times2}lb/gal=\frac{3}{8} lb/gal$
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