Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 5 - Section 5.4 - Multiplication of Monomials - Exercise - Page 223: 20

Answer

$$\frac{4}{3}m^6n^8q^3 .$$

Work Step by Step

By multiplying the numerical coefficients and adding the powers of the variables, we get $$ \left(\frac{3}{5}m^4n^7\right)\left(\frac{20}{9}m^2nq^3\right)=\frac{20}{15}m^6n^8q^3=\frac{4}{3}m^6n^8q^3 .$$
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