Answer
$\frac{3}{16}x^3 y^5z^3$
Work Step by Step
By multiplying the numerical coefficients and adding the powers of the variables, we get
$$
\left(\frac{2}{3}x^2y\right)\left(\frac{9}{32}x y^4z^3\right)=\frac{2\times9}{3\times32}x^3 y^5z^3=\frac{3}{16}x^3 y^5z^3
.$$
