Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 3 - Section 3.4 - Volume and Area - Exercise - Page 147: 51

Answer

$$0.675 \ ha.$$

Work Step by Step

The area of the field is $$75 \times 90 m^2=6750 \ m^2.$$ Now change it to $ha$ by dividing by $10^4$; that is: $$6750 \ m^2= \frac{6750}{10^4}\ ha =0.675 \ ha.$$
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