Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Section 2.7 - Engineering Notation - Exercises - Page 130: 29

Answer

$$588\times 10^{12}.$$

Work Step by Step

By subtracting the exponents and dividing the like terms, we have $$\frac{ 70.5\times 10^6 }{120\times 10^{-9}}=\frac{ 70.5}{120} \times 10^{6-(-9)} \\ =0.588\times 10^{15} =588\times 10^{12}.$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.