Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Section 2.7 - Engineering Notation - Exercises - Page 130: 28

Answer

$$48.0\times 10^{-24} .$$

Work Step by Step

By adding the exponents and multiplying the like terms, we have $$ (6\times 10^{-12} ) (20\times 10^{-9}) (400\times 10^{-6})\\ =(6) (20) (400) \times 10^{-12-9-6}\\ =48,000\times 10^{-27}=48.0 \times 10^{-24} .$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.