Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Section 2.6 - Scientific Notation - Exercises - Page 127: 82

Answer

$$4.09\times 10^{21}.$$

Work Step by Step

We have $$\left(\frac{ 0.259\times 6300 }{866\times 0.013 }\right)^{10}=\left(\frac{ (2.59\times10^{-1})(6.3\times10^3)}{(8.66\times10^2)(1.3\times10^{-2}) }\right)^{10} \\ =\left(\frac{ 1.631\times 10^3}{1.1258\times 10^{1} }\right)^{10}\\ =(1.45\times 10^2)^{10}=4.09\times 10^{21}.$$
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