Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Section 2.6 - Scientific Notation - Exercises - Page 127: 69

Answer

$$1.1 \times 10^{-25} .$$

Work Step by Step

We simplify by raising each factor to the exponent and then we divide: $$ \left(\frac{2.5 \times 10^{-4}}{7.5 \times 10^{8}}\right)^2=\frac{(2.5 \times 10^{-4})^2}{(7.5 \times 10^{8})^2}\\ =\frac{6.25 \times 10^{-8}}{56.25 \times 10^{16}}=\frac{6.25}{56.25 } \times 10^{-8-16}\\=0.11 \times 10^{-24}=1.1 \times 10^{-25} .$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.