Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Review - Page 133: 49

Answer

$$24.3\times 10^{-15} $$

Work Step by Step

By subtracting the exponents and dividing the like terms, we have $$\frac{84.5\times 10^{-9}}{3.48\times 10^{6}}=24.3\times 10^{-15} $$ which is in the engineering notation.
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