Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Review - Page 133: 27

Answer

$$\frac{1} {10^{12}} . $$

Work Step by Step

We have $$(10^{-4} )^{3} =10^{-12}=\frac{1} {10^{12}} . $$
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