Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 15 - Section 15.5 - Mean Measurement - Exercise - Page 515: 15

Answer

$30,292 \ mi$

Work Step by Step

The mean measurement is given by $$ \frac{1}{6}( 25,740 \ mi+ 32,160\ mi+41,005 \ mi+ 21,612\ mi+ 35,424 \ mi+ 25,810\ mi ) = 30,291.833 \ mi\approx 30,292 \ mi .$$
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