Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.5 - Circles - Exercise - Page 410: 26

Answer

number of pipes $\approx11$ pipes

Work Step by Step

The cross-sectional area of a pipe with a $5~in$ diameter can be calculated using the formula $A=\frac{\pi}{4}d^{2}$. Where $d=5in$ So, $A=\frac{\pi}{4}(5in)^{2}=19.63in^{2}$ And the cross-sectional area of a pipe with a $1.5~in$ diameter can be calculated using the same formula. Where $d=1.5in$ So, $A=\frac{\pi}{4}(1.5in)^{2}=1.77in^{2}$ To find the number of pipes needed, we divide the area of the $5~in$ pipe by the area of the $1.5~in$ pipe. Thus, we have: number of pipes $=\frac{19.63in^{2}}{1.77in^{2}}=11.09\approx11$ pipes
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