Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.1 - Angles and Polygons - Exercise - Page 388: 22

Answer

$x=55^o$.

Work Step by Step

We know that $\angle 1=\angle 3$ because they are alternate-exterior angles, so $$3x-50=x+60\Longrightarrow 2x=110$$ and hence $x=55^o$.
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