Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.9 - The U.S. System of Weights and Measures - Exercises - Page 54: 49

Answer

75 ft/min

Work Step by Step

$\frac{4500ft}{1h}\times\frac{1h}{60min}=\frac{4500ft}{60min}=75ft/min$
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