Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.9 - The U.S. System of Weights and Measures - Exercises - Page 53: 30

Answer

$4\frac{1}{6}$ mi

Work Step by Step

$22,000ft=22,000ft\times\frac{1mi}{5280ft}=\frac{22,000}{5280}mi=4\frac{880}{5280}mi=4\frac{1}{6}mi$
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