Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.7 - Addition and Subtraction of Fractions - Exercise - Page 40: 43

Answer

$11\frac{5}{16}$

Work Step by Step

We combine the fractions by finding the LCD and simplify if necessary: $3\displaystyle \frac{9}{16}+4\frac{7}{12}+3\frac{1}{6}=3\displaystyle \frac{27}{48}+4\frac{28}{48}+3\frac{8}{48} =10\displaystyle \frac{63}{48}=10\frac{21}{16}=11\frac{5}{16}$
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