Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Review: 33

Answer

$13\dfrac{11}{25}$

Work Step by Step

Convert each number to an improper fraction to obtain: $=\dfrac{5(1)+4}{5} \div \dfrac{16(1)+9}{16} \times \dfrac{3(11)+2}{3} \\=\dfrac{9}{5}\div \dfrac{25}{16} \times \dfrac{35}{3}$ Perform division first. Use the rule $\dfrac{a}{b} \div \dfrac{c}{d} = \dfrac{a}{b} \times \dfrac{d}{c}$ to obtain: $\require{cancel} =\dfrac{9}{5} \times \dfrac{16}{25} \times \dfrac{35}{3}$ Cancel common factor then multiply to obtain: $\require{cancel} =\dfrac{\cancel{9}^3}{\cancel{5}} \times \dfrac{16}{25} \times \dfrac{\cancel{35}^7}{\cancel{3}} \\=\dfrac{3(16)(7)}{25} \\=\dfrac{336}{25} \\=13\dfrac{11}{25}$
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