Answer
No, see solution.
Work Step by Step
$Au=\begin{bmatrix}
3\\8\\2
\end{bmatrix}$
$Av=\begin{bmatrix}
7\\2\\8
\end{bmatrix}$
$||Au-b||=\sqrt{24}$ and $||Av-b||=\sqrt{24}$. Because the distance from Au to b is equal to the distance from Av to b even though u and v are not equal, neither can be a least squares solution to b.
