Answer
$R=\begin{bmatrix}
7&7\\0&7
\end{bmatrix}$
Work Step by Step
$R=Q^TA$
$R=\begin{bmatrix}
-2/7&5/7&2/7&4/7\\5/7&2/7&-4/7&2
\end{bmatrix}\begin{bmatrix}
-2&3\\5&7\\2&-2\\4&6
\end{bmatrix}=\begin{bmatrix}
7&7\\0&7
\end{bmatrix}$
Linear Algebra and Its Applications (5th Edition)
by Lay, David C.; Lay, Steven R.; McDonald, Judi J.
Published by
Pearson
ISBN 10:
032198238X
ISBN 13:
978-0-32198-238-4
Chapter 6 - Orthogonality and Least Squares - 6.4 Exercises - Page 361: 14
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