Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 6 - Orthogonality and Least Squares - 6.4 Exercises - Page 361: 13

Answer

$R=\begin{bmatrix} 6&12\\0&6 \end{bmatrix}$

Work Step by Step

$R=Q^TA$ $R=\begin{bmatrix} 5/6&1/6&-3/6&1/6\\-1/6&5/6&1/6&3/6 \end{bmatrix}\begin{bmatrix} 5&9\\1&7\\-3&-5\\1&5 \end{bmatrix}=\begin{bmatrix} 6&12\\0&6 \end{bmatrix}$
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