Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 6 - Orthogonality and Least Squares - 6.1 Exercises - Page 338: 11

Answer

$\vec{u}=\begin{bmatrix} 7/\sqrt{69}\\ 2/\sqrt{69}\\ 4/\sqrt{69} \end{bmatrix}$

Work Step by Step

$\vec{v}=\begin{bmatrix} 7\\ 2\\ 4 \end{bmatrix}$ $||\vec{v}||=\sqrt{\vec{v}\cdot\vec{v}}=\sqrt{7^2+2^2+4^2}=\sqrt{69}$ $\vec{u}=\frac{\vec{v}}{||\vec{v}||}=\begin{bmatrix} 7/\sqrt{69}\\ 2/\sqrt{69}\\ 4/\sqrt{69} \end{bmatrix}$
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