Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 5 - Eigenvalues and Eigenvectors - 5.3 Exercises - Page 288: 6

Answer

$\lambda=5:\begin{bmatrix} -2\\0\\1 \end{bmatrix}, \begin{bmatrix} 0\\1\\0 \end{bmatrix}$ $\lambda=4:\begin{bmatrix} -1\\2\\0 \end{bmatrix}$

Work Step by Step

$\lambda=5:\begin{bmatrix} -2\\0\\1 \end{bmatrix}, \begin{bmatrix} 0\\1\\0 \end{bmatrix}$ $\lambda=4:\begin{bmatrix} -1\\2\\0 \end{bmatrix}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.

GradeSaver will pay $15 for your literature essays
GradeSaver will pay $25 for your college application essays
GradeSaver will pay $50 for your graduate school essays – Law, Business, or Medical
GradeSaver will pay $10 for your Community Note contributions
GradeSaver will pay $500 for your Textbook Answer contributions