Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 5 - Eigenvalues and Eigenvectors - 5.2 Exercises - Page 282: 10

Answer

P=−λ3+14λ+12

Work Step by Step

Given Information We are given with an matrix A: A= 0 3 1 3 0 2 1 2 0 We have to find the characteristic polynomial of above matrix. Step-1: The characteristic Equation Write the characteristic equation:|A−λI|= 0 3 1 3 0 2 1 2 0 −λ* 1 0 0 0 1 0 0 0 1 = 0 3 1 3 0 2 1 2 0 − λ 0 0 0 λ 0 0 0 λ = −λ 3 1 3 −λ 2 1 2 −λ Step-2: The characteristic polynomial P= −λ 3 1 3 −λ 2 1 2 −λ =−λ(λ2−4)−3(−3λ−2)+1(6+λ)=−λ3+4λ+9λ+6+6+λ=−λ3+14λ+12 Hence, the characteristic polynomial is: The characteristic polynomial is: P=−λ3+14λ+12
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.