Answer
See solution
Work Step by Step
a. the vector $[\vec{b}_1]_B$ has a 1 on the first row and 0 on all other rows, meaning $Q[\vec{b}_1]_B$ will be the first column of matrix Q.
b. $Q[\vec{b}_k]_B$
c. The vector $[\vec{b}_k]_B$ has 1 on the kth row and 0 on all other rows.