Answer
$dim\,row A=3$
Work Step by Step
Given the null space of a 8 x 5 matrix, A, is 2-dimensional;
We are required to find the dimension of the row space of A
$Rank=n-dim\,Nul A$
$n=5$ and $dim\,Nul A=2$
therefore;
$Rank A=5-2=3$
the rank of a matrix is equal to the number of pivot rows.
the number of pivot rows is equal to the dimension of the row space of A=3.
the dimension of the row space of $A=3$
