Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 4 - Vector Spaces - 4.4 Exercises - Page 225: 28

Answer

There are no free variables, hence the given set is linearly independent

Work Step by Step

Given Polynomial: $1 - 2 t ^ { 2 } - t ^ { 3 } , t + 2 t ^ { 3 } , 1 + t - 2 t ^ { 2 }$ we need to convert the polynomials into vectors; $1 - 2 t ^ { 2 } - t ^ { 3 }=\begin{bmatrix}1\\0\\-2\\1\end{bmatrix}$ $0 + t + 2 t ^ { 3 } =\begin{bmatrix}0\\1\\0\\2\end{bmatrix}$ $1 + t - 2 t ^ { 2 }=\begin{bmatrix}1\\1\\-2\\0\end{bmatrix}$ We combine an Augumented Matrix form the vectors $\begin{bmatrix}1&0&1&0\\{ 0}&{1}&1&0\\-2&0&-2&0\\-1&2&0&0\end{bmatrix}\sim\begin{bmatrix}1&0&1&0\\0&1&1&0\\0&0&-1&0\\0&0&0&0\end{bmatrix}$ This show that there are no free variables, hence the given set is linearly independent
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