Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 4 - Vector Spaces - 4.2 Exercises - Page 207: 1

Answer

$ w\in$Nul A

Work Step by Step

By definition, Nul A =$\{$x$: $ x$\in \mathbb{R}^{n}$ and Ax=0 $\}$. --------- $Aw=\left[\begin{array}{lll} 3 & -5 & -3\\ 6 & -2 & 0\\ -8 & 4 & 1 \end{array}\right]\left[\begin{array}{l} 1\\ 3\\ -4 \end{array}\right]$ $=\left[\begin{array}{l} 3-15+12\\ 6-6+0\\ -8+12-4 \end{array}\right]=\left[\begin{array}{l} 0\\ 0\\ 0 \end{array}\right]$ $Aw=0$, so $ w\in$Nul A
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