Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 3 - Determinants - 3.2 Exercises - Page 177: 21

Answer

This matrix is not invertible.

Work Step by Step

We use the trick in the picture: $$ \left|\begin{matrix} 2&6&0\\1&3&2\\3&9&2 \end{matrix}\right|=2\cdot3\cdot2+6\cdot2\cdot3+0\cdot4\cdot9-3\cdot3\cdot0-9\cdot2\cdot2-2\cdot1\cdot6\\=12+36+0-0-36-12=0 $$ Since the determinant is equal to $0$, then we have, from theorem 4, that the matrix is not invertible.
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