Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 2 - Matrix Algebra - 2.9 Exercises - Page 160: 13

Answer

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Work Step by Step

The basis for the subspace include the pivot columns of matrix $\begin{bmatrix} 1&-3&2&-4\\ -3&9&-1&5\\ 2&-6&4&-3\\ -4&12&2&7 \end{bmatrix} $ After row reducing, we can see columns 1, 3, and 4 are pivot columns. The basis for the subspace is $\begin{bmatrix} 1\\ -3\\ 2\\ -4 \end{bmatrix} $, $\begin{bmatrix} 2\\ -1\\ 4\\ 2 \end{bmatrix} $, and $\begin{bmatrix} -4\\ 5\\ -3\\ 7 \end{bmatrix} $ and the dimension is 3.
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