Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 2 - Matrix Algebra - 2.8 Exercises - Page 154: 31

Answer

See solution.

Work Step by Step

Because Col F is not equal to $R^{5}$, matrix F has pivots less than 5. This means F has nullity more than 0. Because F has a pivot less than # of columns, Nul F does not span a zero space and its basis has at least 1 non zero vectors.
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