Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 2 - Matrix Algebra - 2.7 Exercises - Page 147: 15

Answer

(12,-6,-3)

Work Step by Step

$\operatorname{Let}(X, Y, Z, H)=\left(\frac{1}{2},-\frac{1}{4},-\frac{1}{8}, \frac{1}{24}\right)$ Corresponding point in $\mathbb{R}^{3}$ has coordinates: $(x, y, z)=\left(\frac{X}{H}, \frac{Y}{H}, \frac{Z}{H}\right)=\left(\frac{1 / 2}{1 / 24}, \frac{-1 / 4}{1 / 24}, \frac{-1 / 8}{1 / 24}\right)=(12,-6,-3)$
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