Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 2 - Matrix Algebra - 2.7 Exercises - Page 146: 4

Answer

See solution

Work Step by Step

\[ S=\left[\begin{array}{ccc} .8 & 0 & 0 \\ 0 & 1.2 & 0 \\ 0 & 0 & 1 \end{array}\right] \] Scale Matrix \[ T=\left[\begin{array}{ccc} 1 & 0 & -2 \\ 0 & 1 & 3 \\ 0 & 0 & 1 \end{array}\right] \] Translation matrix \[ A=S T \] Matrix to Find out \[ A=\left[\begin{array}{ccc} .8 & 0 & 0 \\ 0 & 1.2 & 0 \\ 0 & 0 & 1 \end{array}\right]\left[\begin{array}{ccc} 1 & 0 & -2 \\ 0 & 1 & 3 \\ 0 & 0 & 1 \end{array}\right]=\left[\begin{array}{ccc} .8 & 0 & -1.6 \\ 0 & 1.2 & 3.6 \\ 0 & 0 & 1 \end{array}\right] \]
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