Answer
$\left[\begin{array}{c}83 \\ 131 \\ 110\end{array}\right]$
Work Step by Step
\[
I-C=\left[\begin{array}{ccc}
1 & 0 & 0 \\
0 & 1 & 0 \\
0 & 0 & 1
\end{array}\right]-\left[\begin{array}{ccc}
.2 & .2 & 0 \\
.3 & .1 & .3 \\
.1 & 0 & .2
\end{array}\right]=\left[\begin{array}{ccc}
.8 & -.2 & 0 \\
-.3 & .9 & -.3 \\
-.1 & 0 & .8
\end{array}\right]
\]
Get the value of $\mathrm{I}-\mathrm{C}$.
\[
\left[\begin{array}{cccc}
.8 & -.2 & 0 & 40 \\
-.3 & .9 & -.3 & 60 \\
-.1 & 0 & .8 & 80
\end{array}\right]
\]
Augmented matrix to find the value of $x$ in
\[
\begin{array}{cccc}
& & & (\mathrm{I}-\mathrm{C}) \mathrm{X}=\mathrm{d} \\
{\left[\begin{array}{ccc}
.8 & -.2 & 0 & 40 \\
-.3 & .9 & -.3 & 60 \\
-.1 & 0 & .8 & 80
\end{array}\right] \sim\left[\begin{array}{cccc}
1 & 0 & 0 & 82.76 \\
0 & 1 & 0 & 131.03 \\
0 & 0 & 1 & 110.34
\end{array}\right]}
\end{array}
\]
Row reduce the augmented matrix.
\[
\mathbf{x} \approx\left[\begin{array}{c}
83 \\
131 \\
110
\end{array}\right]
\]
