Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 2 - Matrix Algebra - 2.3 Exercises - Page 117: 18

Answer

It is IMPOSSIBLE for the equation to have more than one solution.

Work Step by Step

PROOF: $C\vec{x}=\vec{v}$ is consistent for every $\vec{v}$ in $\mathbb{R}^6$ equals $C\vec{x}$ maps $\vec{x}$ onto $\mathbb{R}^6$. By Theorem 8 clause (i), $C$ is invertible. Also by Theorem 8 (a) and (f): $C$ is invertible. $\leftrightarrow$ $C\vec{x}=\vec{v}$ is one-to-one mapping. So there is only one $\vec{x}$ solution for every $\vec{v}$ in $C\vec{x}=\vec{v}$.
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