Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 2 - Matrix Algebra - 2.2 Exercises - Page 112: 17

Answer

$A=BCB^{-1}$

Work Step by Step

$AB=BC\qquad $ ... Right-multiply with $B^{-1}:$ $ABB^{-1}=BCB^{-1}$ $A(BB^{-1})=BCB^{-1}$ $AI=BCB^{-1}$ $A=BCB^{-1}$
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