Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 2 - Matrix Algebra - 2.1 Exercises - Page 102: 1

Answer

-2A=[-4 0 2 ; -8 10 -4] B-2A=[3 -5 3 ; -7 6 -7] AC is undefined CD=[1 13 ; -7 -6]

Work Step by Step

I will express matrices as ( A B C ; D E F ), where the entries listed go across columns and then break to a new row and column one after each ";". We want to find: -2A=-2(2 0 -1 ; 4 -5 2)=(-4 0 2 ; -8 10 -4) B-2A=[7 -5 1 ; 1 -4 -3[+[-4 0 2 ; -8 10 -4]=[3 -5 3; -7 6 -7] AC=undefined. The reason for this is that the # of columns of A must be equal to the # of rows in C, because of the law for matrix multiplication. 3 is not equal to 2. CD=[1 2 ; -2 1][3 5 ; -1 4]=[3*1-1*2 5*1+4*2 ; 3*-2+1*-1 -2*5+1*4]=[1 13 ; -7 -6]
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