Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 1 - Linear Equations in Linear Algebra - Problems - Page 32: 11

Answer

$b$ is a linear combination of $a_1, a_2, a_3$.

Work Step by Step

$b=2a_1+3a_2$. To solve this, we first construct the top value of $b$, 2, out of our available 1, 0, and 5. We know we want something even and comparatively small, so $2a_1$ is the most simple construction. Next, we try to make the second position of $b$, 11, out of -2, 5, and 0 without disturbing our creation of the 2. Because the top value of $a_2$ is 0, we can use 2(-2)+3(1)=-1, as desired. To check our solution, we look at the third position of $b$, 6, and see that we can construct it by 2(0)+3(2). Thus, $b$ is a linear combination of $a_1, a_2, a_3$ because $b=2a_1+3a_2$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.