Answer
$(0,1,0,0),(1,0,0,0)$.
Work Step by Step
Plugging in $t=0$ and $z=0$ into the third equation, we get $x+y=1$. Thus $x=0,y=1$ and $x=1,y=0$ satisfy that equation. Thus two points on the line of intersection are $(0,1,0,0),(1,0,0,0)$.
Linear Algebra and Its Applications, 4th Edition
by Strang, Gilbert
Published by
Brooks Cole
ISBN 10:
0030105676
ISBN 13:
978-0-03010-567-8
Chapter 1 - Section 1.2 - The Geometry of Linear Equations - Problem Set - Page 9: 5
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
