Chapter 9 - Section 9.5 - Graphs of Quadratic Equations - Exercise Set - Page 665: 14

$\text{$y-$intercept: } 3$

Setting $x=0$ and then solving for $y$, then the $y-$intercept of the given equation, $ y=-x^2-2x+3 ,$ is \begin{array}{l}\require{cancel} y=-(0)^2-2(0)+3 \\\\ y=-0+0+3 \\\\ y=3 .\end{array} Hence, the $y-$intercept is \begin{array}{l}\require{cancel} \text{$y-$intercept: } 3 .\end{array}