Chapter 9 - Section 9.5 - Graphs of Quadratic Equations - Exercise Set - Page 665: 12

$\text{$y-$intercept: } 5 $

Setting $x=0$ and then solving for $y$, then the $y-$intercept of the given equation, $ y=x^2-6x+5 ,$ is \begin{array}{l}\require{cancel} y=(0)^2-6(0)+5 \\\\ y=5 .\end{array} Hence, the $y-$intercept is \begin{array}{l}\require{cancel} \text{$y-$intercept: } 5 .\end{array}