Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 9 - Section 9.1 - Solving Quadratic Equations by the Square Root Property - Exercise Set - Page 633: 80

Answer

7 feet

Work Step by Step

Let x be the length of a side of the original square. If the area of the new square is 169 square meters then: $169=(x+3+3)^2$ Simplify. $169=(x+6)^2$ Take the square root of each side. $\sqrt{169}=\sqrt{(x+6)^2}$ Simplify. $13=x+6$ Subtract 6 from each side. $13-6=x+6-6$ Simplify. $7=x$
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