# Chapter 9 - Section 9.1 - Solving Quadratic Equations by the Square Root Property - Exercise Set: 28

$x=\left\{ -7-\sqrt{5},-7+\sqrt{5} \right\}$

#### Work Step by Step

Taking the square root of both sides (the Square Root Property), the solutions to the given equation, $(y+7)^2=5 ,$ are \begin{array}{l}\require{cancel} y+7=\pm\sqrt{5} \\\\ y=-7\pm\sqrt{5} .\end{array} Hence, $x=\left\{ -7-\sqrt{5},-7+\sqrt{5} \right\} .$

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