Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 9 - Section 9.1 - Solving Quadratic Equations by the Square Root Property - Exercise Set: 19

Answer

$x=\{ -1,7 \} $

Work Step by Step

Taking the square root of both sides (the Square Root Property), the solutions to the given equation, $ (x-3)^2=16 ,$ are \begin{array}{l}\require{cancel} (x-3)=\pm\sqrt{16} \\\\ x-3=\pm\sqrt{(4)^2} \\\\ x-3=\pm4 \\\\ x=3\pm4 .\end{array} Hence, $ x=\{ -1,7 \} .$
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