Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 9 - Section 9.1 - Solving Quadratic Equations by the Square Root Property - Exercise Set: 13

Answer

$x=\pm5$

Work Step by Step

Using the properties of equality, the given equation, $ 2x^2+1=51 ,$ is equivalent to \begin{array}{l}\require{cancel} 2x^2=51-1 \\\\ 2x^2=50 \\\\ x^2=\dfrac{50}{2} \\\\ x^2=25 .\end{array} Taking the square root of both sides, then the solutions of the given equation are \begin{array}{l}\require{cancel} x=\pm\sqrt{25} \\\\ x=\pm\sqrt{(5)^2} \\\\ x=\pm5 .\end{array}
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