Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.6 - Rational Exponents - Exercise Set: 11

Answer

$-2$

Work Step by Step

RECALL: (i) $a^{\frac{1}{5}}=\sqrt[5]{a}$ (ii) $\sqrt[5]{a^5}=a$ Use rule (i) above to obtain: $=-\sqrt[5]{32}$ Write 32 as $2^5$: $=-\sqrt[5]{2^5}$ Use rule (ii) above to obtain: $=-2$
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