## Introductory Algebra for College Students (7th Edition)

$7x^2\sqrt{x}$
Getting the perfect factors and then extracting its root, the simplified form of the given expression, $\sqrt{49x^{5}} ,$ is \begin{array}{l}\require{cancel} \sqrt{49x^{4}\cdot x} \\\\= \sqrt{(7x^2)^2\cdot x} \\\\= 7x^2\sqrt{x} .\end{array} Note that variables are assumed to represent positive real numbers.