Answer
$x\leq6$
Work Step by Step
For $\sqrt{12-2x}$ to be a real number, $12-2x$ must be non-negative.
$12-2x\geq0$
Add 2x to both sides of the inequality and simplify.
$12-2x+2x\geq0+2x$
$12\geq2x$
Divide both sides of the inequality by 2 and simplify.
$12\div2\geq2x\div2$
$6\geq x$
