Answer
all real numbers
Work Step by Step
For $\sqrt{x^2+3}$ to be a real number, $x^2+3$ must be non-negative.
$x^2+3\geq0$
Subtract 3 from both sides of the inequality and simplify.
$x^2+3-3\geq0-3$
$x^2\geq-3$
Since $x^2$ is always non-negative, the expression is true for all real number values of x.
