Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Mid-Chapter Check Point - Page 594: 5

Answer

$9\sqrt3$

Work Step by Step

$\sqrt{27}+3\sqrt{12}$ Factor out perfect squares. $\sqrt{(9)(3)}+3\sqrt{(4)(3)}$ Simplify. $3\sqrt3+(3)(2)\sqrt3$ $3\sqrt3+6\sqrt3$ Combine like radicals. $9\sqrt3$
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