Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Exercise Set - Page 499: 47

Answer

$\displaystyle \frac{y}{3}$

Work Step by Step

Dividing with $\displaystyle \frac{P}{Q}$ equals multiplying with the reciprocal, $\displaystyle \frac{Q}{P}.$ $ \displaystyle \frac{y^{2}-y}{15}\div\frac{y-1}{5}=\frac{y^{2}-y}{15}\cdot\frac{5}{y-1}\qquad$... factor what you can $=\displaystyle \frac{y(y-1)}{15}\cdot\frac{5}{(y-1)}\qquad$... divide out the common factors $=\displaystyle \frac{y(1)}{3}\cdot\frac{1}{(1)}$ = $\displaystyle \frac{y}{3}$
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